Triangles — Class 10 Maths MCQ with Answers (2026-27)
Updated · checked against the CBSE 2026-27 syllabus
12 objective questions on Triangles, every one checked against the CBSE 2026-27 syllabus. Pick an option and the correct answer is shown straight away, with your marks running at the top. A new question opens each day until all 12 are unlocked.
What the 2026-27 syllabus covers in Triangles
- Definitions, examples and counter examples of similar triangles
- (Prove) Basic Proportionality Theorem
- (State) Converse of the Basic Proportionality Theorem
- AAA, SSS and SAS criteria for similarity of triangles
Triangles MCQ questions with answers
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Vijay is trying to find the height of a tower using similar triangles. Vijay's house is 20 m high and casts a shadow 10 m long. At the same time, the tower casts a shadow 50 m long and Ajay's house casts a 20 m shadow. What is the height of the tower?
- 20 m
- 50 m
- 100 m
- 200 m
Answer: c) 100 m
The sun's rays make equal angles, so the triangles are similar and height ÷ shadow is constant. Vijay's ratio is 20/10 = 2, so the tower is 2 × 50 = 100 m.
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What will be the length of the shadow of the tower when Vijay's house casts a shadow of 12 m?
- 75 m
- 50 m
- 45 m
- 60 m
Answer: d) 60 m
Corresponding sides are proportional: tower shadow = 100 × (12/20) = 60 m.
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What is the height of Ajay's house?
- 30 m
- 40 m
- 50 m
- 20 m
Answer: b) 40 m
Using the same ratio of 2, Ajay's house is 2 × 20 = 40 m high.
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When the tower casts a shadow of 40 m, what will be the length of the shadow of Ajay's house at the same time?
- 16 m
- 32 m
- 20 m
- 8 m
Answer: a) 16 m
The tower's height-to-shadow ratio is 100/40 = 2.5, and it is the same for every object at that moment. Ajay's house: 40 ÷ 2.5 = 16 m.
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When the tower casts a shadow of 40 m, what will be the length of the shadow of Vijay's house at the same time?
- 15 m
- 32 m
- 16 m
- 8 m
Answer: d) 8 m
Using the same ratio of 2.5, Vijay's house casts 20 ÷ 2.5 = 8 m.
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A scale drawing of an object is the same shape as the object but a different size; the ratio of two corresponding sides in similar figures is the scale factor. In a photograph of a train engine the scale factor is 1:200. If the length of the model is 11 cm, then the overall length of the engine is
- 22 cm
- 220 cm
- 220 m
- 22 m
Answer: d) 22 m
Scale 1:200 means every 1 cm on the photograph is 200 cm in reality. So 11 × 200 = 2200 cm = 22 m.
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What is the actual width of the door if the width of the door in the photograph is 0.35 cm?
- 0.7 m
- 0.7 cm
- 0.07 cm
- 0.07 m
Answer: a) 0.7 m
0.35 × 200 = 70 cm, which is 0.7 m. Watch the unit conversion — this is where most marks are lost.
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Refer to the figure in your textbook or question paper.
*(Figure required: A at top; AB = x cm along AD; B on AD with BD = 4 cm; BC = 3 cm; DE = 6 cm; BC ∥ DE.)* The length of AB in the given figure is- 8 cm
- 6 cm
- 4 cm
- 10 cm
Answer: c) 4 cm
BC ∥ DE makes △ABC ~ △ADE, so AB/AD = BC/DE. That gives x/(x + 4) = 3/6, so 2x = x + 4 and x = 4 cm.
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Refer to the figure in your textbook or question paper.
*(Figure required: QR ∥ ST, with P, S, Q collinear.)* QR = a, QS = b, SP = c and ST = x. The correct relationship between x, a, b and c is- x = a(b+c)/c
- x = a(b+c)/b
- x = ac/(b+c)
- x = a(b−c)/b
Answer: c) x = ac/(b+c)
ST ∥ QR makes △PST ~ △PQR, so ST/QR = PS/PQ. Since PQ = b + c, x/a = c/(b + c), giving x = ac/(b + c).
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A water tower for a locality is 40 m high. The water tower casts a shadow of 25 m. At the same time, a tree near it casts a shadow of 5 m. What is the height of the tree?
- 3.12 m
- 8 m
- 20 m
- 25 m
Answer: b) 8 m
At the same moment the height-to-shadow ratio is the same for both: 40/25 = h/5, so h = 8 m.
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A scale model of the water tower of 100 cm height is created. The height of its pillars is 75 cm each. What is the height of a pillar (in m) in the actual water tower?
- 7.5
- 25
- 30
- 53.4
Answer: c) 30
The model is 100 cm = 1 m tall for a real tower of 40 m, a scale factor of 40. So the pillar is 0.75 × 40 = 30 m.
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Refer to the figure in your textbook or question paper.
*(Figure required: a dollhouse roof; triangles ABC equilateral with side 45 cm; DE and GF parallel to the floor divide AB and AC into three equal parts.)* Which criterion of similar triangles does not apply to triangles AGF and ADE?- AAA
- SSS
- SAS
- RHS
Answer: d) RHS
AAA, SSS and SAS are all criteria for similarity. RHS is a congruence criterion for right triangles, so it does not apply here.
Frequently asked questions
How many Triangles MCQs are there for Class 10 Maths?
This page has 12 multiple choice questions on Triangles, each with the correct answer and a worked explanation. Every question has been checked against the CBSE 2026-27 syllabus.
Which topics have been removed from Triangles in the 2026-27 syllabus?
The following are no longer assessed in 2026-27: Pythagoras Theorem and its converse; Ratio of the areas of two similar triangles. Questions on these carry no marks, so they are not included here.
Is Pythagoras Theorem still in the Class 10 Maths syllabus?
No. Pythagoras Theorem is not part of the CBSE 2026-27 Class 10 Maths syllabus for Triangles. Many question banks online still include it, but it carries no marks this session.
What does the 2026-27 syllabus cover in Triangles?
Definitions, examples and counter examples of similar triangles; (Prove) Basic Proportionality Theorem; (State) Converse of the Basic Proportionality Theorem; AAA, SSS and SAS criteria for similarity of triangles. Every question on this page tests one of these.
How many marks is each Triangles MCQ worth?
Each objective question carries 1 mark in the CBSE Class 10 Maths paper. The practice set on this page keeps a running total as you answer, so you can see your score out of 12.
Triangles — chapter notes
Two triangles are similar when their angles match and their corresponding sides are in the same ratio — same shape, different size. Three criteria establish it: AAA, SSS and SAS. Note that RHS is a congruence criterion, not a similarity one, and questions do test that distinction. The theorem to prove is the Basic Proportionality Theorem: a line drawn parallel to one side of a triangle divides the other two sides in the same ratio.
Its converse is stated, not proved. In practice, whenever a figure shows a line parallel to a side, BPT is what you reach for. The everyday application is shadows: at one moment every upright object has the same height-to-shadow ratio, so a tower's height follows from a known object's. Set up the proportion as a clear equation before substituting numbers, and keep corresponding sides in the same order on both sides of it.